Find the one-sided limit.
-$$\lim _ { x - 4 ^ { + } } \frac { 16 - x ^ { 2 } } { 4 - x }$$
A) 8
B) 0
C) 4
D) does not exist

Question

Quizplus · Accepted Answer

The expression can be simplified by factoring the numerator: $16 - x^2 = (4 - x)(4 + x)$. Thus, the original expression becomes $\frac{(4 - x)(4 + x)}{4 - x}$. For $x$ approaching 4 from the right, the term $4 - x$ in the denominator and numerator cancels out, leaving $4 + x$. Substituting $x = 4$, we get $4 + 4 = 8$.

Find the One-Sided Limit lim⁡x−4+16−x24−x\lim _ { x - 4 ^ { + } } \frac { 16 - x ^ { 2 } } { 4 - x }x−4+lim​4−x16−x2​

Find the One-Sided Limit $\lim _ { x - 4 ^ { + } } \frac { 16 - x ^ { 2 } } { 4 - x }$