Solve the inequality. Express your answer using interval notation. Graph the solution set.
-$| 8 k + 1 | \geq 2$

A) $\left( - \frac { 3 } { 8 } , \frac { 1 } { 8 } \right)$
B) $\left( - \infty , - \frac { 3 } { 8 } \right] \cup \left[ \frac { 1 } { 8 } , \infty \right)$
C)$\left[\frac{1}{8}, \infty\right)$
D) $\left[ - \frac { 3 } { 8 } , \frac { 1 } { 8 } \right]$

Question

Solve the inequality. Express your answer using interval notation. Graph the solution set.
-$| 8 k + 1 | \geq 2$

A) $\left( - \frac { 3 } { 8 } , \frac { 1 } { 8 } \right)$ 
B) $\left( - \infty , - \frac { 3 } { 8 } \right] \cup \left[ \frac { 1 } { 8 } , \infty \right)$ 
C)$\left[\frac{1}{8}, \infty\right)$ 
D) $\left[ - \frac { 3 } { 8 } , \frac { 1 } { 8 } \right]$

Quizplus · Accepted Answer

The Answer of Solve the inequality. Express your answer using interval notation. Graph the solution set.
-$| 8 k + 1 | \geq 2$

A) $\left( - \frac { 3 } { 8 } , \frac { 1 } { 8 } \right)$ 
B) $\left( - \infty , - \frac { 3 } { 8 } \right] \cup \left[ \frac { 1 } { 8 } , \infty \right)$ 
C)$\left[\frac{1}{8}, \infty\right)$ 
D) $\left[ - \frac { 3 } { 8 } , \frac { 1 } { 8 } \right]$

Solve the Inequality ∣8k+1∣≥2| 8 k + 1 | \geq 2∣8k+1∣≥2

Solve the Inequality $| 8 k + 1 | \geq 2$