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Find the complex zeros of the quadratic function.
-$$f ( x ) = x ^ { 2 } - 36$$
A) $x = 36$
B) $x = 6$
C) $x = 6 , x = - 6$
D) $x = - 6$

Question

Quizplus · Accepted Answer

The complex zeros of the quadratic function $f(x) = x^2 - 36$ can be found by setting the function equal to zero and solving for $x$. This gives $x^2 - 36 = 0$, which simplifies to $x^2 = 36$. Taking the square root of both sides gives $x = \pm6$, which means the zeros are $x = 6$ and $x = -6$.

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