Solve the inequality.
-$$x ^ { 2 } + 6 x \leq 0$$
A) $( - \infty , 0 ]$ or $[ 6 , \infty )$
B) $[ - 6,0 ]$
C) $( - \infty , - 6 ]$ or $[ 0 , \infty )$
D) $[ 0,6 ]$

Question

Quizplus · Accepted Answer

To solve the inequality $x^2 + 6x \leq 0$, factor it to $x(x + 6) \leq 0$. The roots are $x = 0$ and $x = -6$. The inequality holds between these roots, including the endpoints, hence the solution is $[ - 6,0 ]$.

Solve the Inequality x2+6x≤0x ^ { 2 } + 6 x \leq 0x2+6x≤0

Solve the Inequality $x ^ { 2 } + 6 x \leq 0$