Solve the problem.
-The polynomial function $\mathrm { f } ( \mathrm { x } ) = 6 \mathrm { x } ^ { 3 } + 19 \mathrm { x } ^ { 2 } + 8 \mathrm { x } - 5$ has exactly one positive zero.
Use the Intermediate Value Theorem to approximate the zero correct to 2 decimal places.
A) $0.10$
B) $0.66$
C) $0.33$
D) $0.50$

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The Answer of Solve the problem.
-The polynomial function $\mathrm { f } ( \mathrm { x } ) = 6 \mathrm { x } ^ { 3 } + 19 \mathrm { x } ^ { 2 } + 8 \mathrm { x } - 5$ has exactly one positive zero.
Use the Intermediate Value Theorem to approximate the zero correct to 2 decimal places.
A) $0.10$
B) $0.66$
C) $0.33$
D) $0.50$

Solve the Problem f(x)=6x3+19x2+8x−5\mathrm { f } ( \mathrm { x } ) = 6 \mathrm { x } ^ { 3 } + 19 \mathrm { x } ^ { 2 } + 8 \mathrm { x } - 5f(x)=6x3+19x2+8x−5

Solve the Problem $\mathrm { f } ( \mathrm { x } ) = 6 \mathrm { x } ^ { 3 } + 19 \mathrm { x } ^ { 2 } + 8 \mathrm { x } - 5$