Find the x- and y-intercepts of f.
-$$f ( x ) = - x ^ { 2 } ( x + 3 ) \left( x ^ { 2 } + 1 \right)$$
A) $x$-intercepts: $- 3 , - 1,0,1 ; y$-intercept: 0
B) $x$-intercepts: $- 3 , - 1,0 ; y$-intercept: $- 3$
C) $x$-intercepts: $- 3,0$; $y$-intercept: 0
D) $x$-intercepts: $- 3 , - 1,0 ; y$-intercept: 3

Question

Quizplus · Accepted Answer

To find the x-intercepts, set $f(x) = 0$. This gives $-x^2(x+3)(x^2+1) = 0$. The solutions are $x = 0$ and $x = -3$; $x^2 + 1 = 0$ has no real solutions. For the y-intercept, set $x = 0$, which gives $f(0) = 0$.

Find the X- and Y-Intercepts of F f(x)=−x2(x+3)(x2+1)f ( x ) = - x ^ { 2 } ( x + 3 ) \left( x ^ { 2 } + 1 \right)f(x)=−x2(x+3)(x2+1)

Find the X- and Y-Intercepts of F $f ( x ) = - x ^ { 2 } ( x + 3 ) \left( x ^ { 2 } + 1 \right)$