Solve the equation.
-$\log _ { 3 } ( 3 x + 7 ) = \log _ { 3 } ( 3 x + 2 )$
A) $\{ 5 \}$
B) $\{ 0 \}$
C) $\varnothing$
D) $\left\{ \frac { 9 } { 5 } \right\}$

Question

Quizplus · Accepted Answer

Since the logarithms are equal and have the same base, the arguments must be equal. Setting $3x + 7 = 3x + 2$ leads to a contradiction, as no value of $x$ can satisfy this equation. Therefore, there are no solutions.

Solve the Equation log⁡3(3x+7)=log⁡3(3x+2)\log _ { 3 } ( 3 x + 7 ) = \log _ { 3 } ( 3 x + 2 )log3​(3x+7)=log3​(3x+2)

Solve the Equation $\log _ { 3 } ( 3 x + 7 ) = \log _ { 3 } ( 3 x + 2 )$