Express as a single logarithm.
-$\log _ { c } m + \log _ { c } n$
A) $\log _ { \mathrm { C } } \mathrm { mn }$
B) $\log _ { \mathrm { C } } ( \mathrm { mn } )$
C) $\log _ { \mathrm { C } } \mathrm { m } \cdot \log _ { \mathrm { C } } \mathrm { n }$
D) $\log _ { \mathrm { C } } \frac { \mathrm { m } } { \mathrm { n } }$

Question

Quizplus · Accepted Answer

The product rule of logarithms states that $\log _ { c } m + \log _ { c } n = \log _ { c } ( m n )$.

Express as a Single Logarithm log⁡cm+log⁡cn\log _ { c } m + \log _ { c } nlogc​m+logc​n

Express as a Single Logarithm $\log _ { c } m + \log _ { c } n$