Solve the equation.
-$$9 ^ { 2 x } \cdot 27 ^{( 3 - x )} = \frac { 1 } { 9 }$$
A) $\{ - 8 \}$
B) $\{ 10 \}$
C) $\{ - 11 \}$
D) $\left\{ \frac { 9 + \sqrt { 87 } } { 6 } , \frac { 9 - \sqrt { 87 } } { 6 } \right\}$

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The Answer of Solve the equation.
-$$9 ^ { 2 x } \cdot 27 ^{( 3 - x )} = \frac { 1 } { 9 }$$
A) $\{ - 8 \}$
B) $\{ 10 \}$
C) $\{ - 11 \}$
D) $\left\{ \frac { 9 + \sqrt { 87 } } { 6 } , \frac { 9 - \sqrt { 87 } } { 6 } \right\}$

Solve the Equation 92x⋅27(3−x)=199 ^ { 2 x } \cdot 27 ^{( 3 - x )} = \frac { 1 } { 9 }92x⋅27(3−x)=91​

Solve the Equation $9 ^ { 2 x } \cdot 27 ^{( 3 - x )} = \frac { 1 } { 9 }$