Solve the problem using Snell's Law: $$\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }$$
-A light beam in air travels at $2.99 \times 10 ^ { 8 }$ meters per second. If its angle of incidence to a second medium is $42 ^ { \circ }$ and its angle of refraction in the second medium is $32 ^ { \circ }$, what is its speed in the second medium (to two decimal places)?
A) $1.58 \times 10 ^ { 8 } \mathrm { mps }$
B) $3.78 \times 10 ^ { 8 } \mathrm { mps }$
C) $2.37 \times 10 ^ { 8 }$ mps
D) $2.00 \times 10 ^ { 8 } \mathrm { mps }$

Question

Quizplus · Accepted Answer

Using Snell's Law, $\frac{\sin(42^\circ)}{\sin(32^\circ)} = \frac{2.99 \times 10^8}{v_2}$. Solving for $v_2$ gives approximately $2.37 \times 10^8$ mps.

Solve the Problem Using Snell's Law sin⁡θ1sin⁡θ2=v1v2\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }sinθ2​sinθ1​​=v2​v1​​

Solve the Problem Using Snell's Law $\frac { \sin \theta _ { 1 } } { \sin \theta _ { 2 } } = \frac { v _ { 1 } } { v _ { 2 } }$