Solve the equation. Give a general formula for all the solutions.
-$\sin \theta = 1$
A) $\theta = 0 + 2 k \pi$
B) $\theta = \frac { 3 \pi } { 2 } + 2 \mathrm { k } \pi$
C) $\theta = \frac { \pi } { 2 } + 2 \mathrm { k } \pi$
D) $\theta = \pi + 2 k \pi$

Question

Quizplus · Accepted Answer

The sine function equals 1 at $\theta = \frac{\pi}{2}$, and because the sine function is periodic with a period of $2\pi$, all solutions can be represented as $\theta = \frac{\pi}{2} + 2k\pi$, where $k$ is any integer.

Solve the Equation sin⁡θ=1\sin \theta = 1sinθ=1 A) θ=0+2kπ\theta = 0 + 2 k \piθ=0+2kπ

Solve the Equation $\sin \theta = 1$ A) $\theta = 0 + 2 k \pi$