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Transform the Polar Equation to an Equation in Rectangular Coordinates rsecθ=6r \sec \theta = - 6

Question 57

Multiple Choice

Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation.
- rsecθ=6r \sec \theta = - 6
 Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6      A)     B)       (x+3) ^{2}+y^{2}=9 ;   circle, radius 3 center   (-3,0)    in rectangular coordinates  C)       y=-6  ; horizontal line 6 units below the pole D)        x=-6  ; vertical line 6 units to the left of the pole    x^{2}+(y+3) ^{2}=9 ;   circle, radius 3 ,  center at   (0,-3)    in rectangular coordinates


A)
 Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6      A)     B)       (x+3) ^{2}+y^{2}=9 ;   circle, radius 3 center   (-3,0)    in rectangular coordinates  C)       y=-6  ; horizontal line 6 units below the pole D)        x=-6  ; vertical line 6 units to the left of the pole    x^{2}+(y+3) ^{2}=9 ;   circle, radius 3 ,  center at   (0,-3)    in rectangular coordinates

B)
 Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6      A)     B)       (x+3) ^{2}+y^{2}=9 ;   circle, radius 3 center   (-3,0)    in rectangular coordinates  C)       y=-6  ; horizontal line 6 units below the pole D)        x=-6  ; vertical line 6 units to the left of the pole    x^{2}+(y+3) ^{2}=9 ;   circle, radius 3 ,  center at   (0,-3)    in rectangular coordinates
(x+3) 2+y2=9; (x+3) ^{2}+y^{2}=9 ; circle, radius 3
center (3,0) (-3,0) in rectangular coordinates

C)
 Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6      A)     B)       (x+3) ^{2}+y^{2}=9 ;   circle, radius 3 center   (-3,0)    in rectangular coordinates  C)       y=-6  ; horizontal line 6 units below the pole D)        x=-6  ; vertical line 6 units to the left of the pole    x^{2}+(y+3) ^{2}=9 ;   circle, radius 3 ,  center at   (0,-3)    in rectangular coordinates

y=6 y=-6 ; horizontal line 6 units below the pole
D)
 Transform the polar equation to an equation in rectangular coordinates. Then identify and graph the equation. - r \sec \theta = - 6      A)     B)       (x+3) ^{2}+y^{2}=9 ;   circle, radius 3 center   (-3,0)    in rectangular coordinates  C)       y=-6  ; horizontal line 6 units below the pole D)        x=-6  ; vertical line 6 units to the left of the pole    x^{2}+(y+3) ^{2}=9 ;   circle, radius 3 ,  center at   (0,-3)    in rectangular coordinates

x=6 x=-6 ; vertical line 6 units to the left of the pole

x2+(y+3) 2=9; x^{2}+(y+3) ^{2}=9 ; circle, radius 3 ,
center at (0,3) (0,-3) in rectangular coordinates

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