Find the Vertex, Focus, and Directrix of the Parabola $y^{2}+12 y=4 x-16$

Find the vertex, focus, and directrix of the parabola. Graph the equation.
- $y^{2}+12 y=4 x-16$

A) vertex: $( - 5 , - 6 )$
focus: $( - 4 , - 6 )$
directrix: $x = - 6$


B) vertex: $( - 5 , - 6 )$
focus: $( - 6 , - 6 )$
directrix: $x = - 4$


C) vertex: $( - 5 , - 6 )$
focus: $( - 5 , - 7 )$
directrix: $y = - 5$


D) vertex: $( - 5 , - 6 )$
focus: $( - 5 , - 5 )$
directrix: $y = - 7$