Use a truth table to determine whether the argument is valid.
$\begin{array}{l}
\sim p \wedge q \
\frac{r \rightarrow \sim q}{\therefore r}
\end{array}$

Name: Use a truth table to determine whether the argument is valid. $\begin{array}{l} \sim p \wedge q \\ \frac{r \rightarrow \sim q}{\therefore r} \end{array}$
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The Answer is

ext { The argument is not valid. }

\begin{array}{c|c|c|c|c|c|c}p & q & r & (\sim p \wedge q) & (r ightarrow \sim q) & (\sim p \wedge q) \wedge(r ightarrow \sim q) & {[(\sim p \wedge q) \wedge(r ightarrow \sim q}) \& & & & && \Rightarrow r \\hline \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{F} & \mathrm{F} & \mathrm{F} & \mathrm{T} \\mathrm{T} & \mathrm{T} & \mathrm{F} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} \\mathrm{T} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} \\mathrm{T} & \mathrm{F} & \mathrm{F} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} \\mathrm{F} & \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{F} & \mathrm{F} & \mathrm{T} \\mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} & \mathrm{T} & \mathrm{T} & \mathrm{F} \\mathrm{F} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T} \\mathrm{F} & \mathrm{F} & \mathrm{F} & \mathrm{F} & \mathrm{T} & \mathrm{F} & \mathrm{T}\end{array}

Use a Truth Table to Determine Whether the Argument Is ∼p∧qr→∼q∴r\begin{array}{l}\sim p \wedge q \\\frac{r \rightarrow \sim q}{\therefore r}\end{array}∼p∧q∴rr→∼q​​

Use a Truth Table to Determine Whether the Argument Is $\begin{array}{l}\sim p \wedge q \\\frac{r \rightarrow \sim q}{\therefore r}\end{array}$