The table displays the probabilities for each of the six outcomes when rolling a particular unfair die. Suppose that the die is rolled once. Let A be the event that the number rolled is less than 4, and let B be the event that the number rolled is odd. Find $P ( A \cap B )$ $$\begin{array} { | l | l | l | l | l | l | l | }
\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \
\hline \text { Probability } & .1 & .1 & .1 & .2 & .2 & .3 \
\hline
\end{array}$$
A) .7
B) .2
C) .5
D) .3

Question

The table displays the probabilities for each of the six outcomes when rolling a particular unfair die. Suppose that the die is rolled once. Let A be the event that the number rolled is less than 4, and let B be the event that the number rolled is odd. Find $P ( A \cap B )$ $$\begin{array} { | l | l | l | l | l | l | l | } 
\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \
\hline \text { Probability } & .1 & .1 & .1 & .2 & .2 & .3 \
\hline
\end{array}$$
A) .7
B) .2
C) .5
D) .3

Quizplus · Accepted Answer

Event A (number rolled is less than 4) includes outcomes 1, 2, and 3. Event B (number rolled is odd) includes outcomes 1, 3, and 5. The intersection $A \cap B$ includes outcomes 1 and 3. The probability is $0.1 + 0.1 = 0.2$.

The Table Displays the Probabilities for Each of the Six P(A∩B)P ( A \cap B )P(A∩B)

The Table Displays the Probabilities for Each of the Six $P ( A \cap B )$