Factor by any method.
-$$( p - q ) ^ { 2 } + 20 ( p - q ) + 100$$
A) $( p - q + 10 ) ^ { 2 }$
B) $( p - q + 10 ) ( p - q - 10 )$
C) prime
D) $( p - q + 100 ) ( p - q )$

Question

Quizplus · Accepted Answer

This expression is a perfect square trinomial, factoring to $(p - q + 10)^2$, because $20(p - q)$ is twice the product of the square root of $(p - q)^2$ and $10$, and $100$ is $10^2$.

Factor by Any Method (p−q)2+20(p−q)+100( p - q ) ^ { 2 } + 20 ( p - q ) + 100(p−q)2+20(p−q)+100

Factor by Any Method $( p - q ) ^ { 2 } + 20 ( p - q ) + 100$