Factor the trinomial, if possible.
-$$9 x ^ { 2 } - 39 x - 30$$
A) $( 3 x + 2 ) ( 3 x - 15 )$
B) $3 ( 3 x + 2 ) ( x - 5 )$
C) $( 9 x + 6 ) ( x - 5 )$
D) $3 ( 3 x - 2 ) ( x + 5 )$

Question

Quizplus · Accepted Answer

The correct factorization of $9x^2 - 39x - 30$ is obtained by first factoring out the greatest common factor (GCF), which is 3, resulting in $3(3x^2 - 13x - 10)$. Then, by finding two numbers that multiply to $3 \times -10 = -30$ and add to -13 (which are -15 and +2), the trinomial can be factored as $3(3x + 2)(x - 5)$.

Factor the Trinomial, If Possible 9x2−39x−309 x ^ { 2 } - 39 x - 309x2−39x−30

Factor the Trinomial, If Possible $9 x ^ { 2 } - 39 x - 30$