Factor by grouping.
-$10 x ^ { 2 } + 25 x y - 12 x y - 30 y ^ { 2 }$
A) $( 5 x - 6 y ) ( 2 x + 5 y )$
B) $( 10 x - 6 y ) ( x + 5 y )$
C) $( 5 x - 6 ) ( 2 x + 5 )$
D) $( 5 x + 6 y ) ( 2 x + 5 y )$

Question

Quizplus · Accepted Answer

First, group the terms: $10x^2 + 25xy$ and $-12xy - 30y^2$. Factoring out the greatest common factor from each group gives $5x(2x + 5y) - 6y(2x + 5y)$. Then, factor out the common binomial factor $(2x + 5y)$, resulting in $(5x - 6y)(2x + 5y)$.

Factor by Grouping 10x2+25xy−12xy−30y210 x ^ { 2 } + 25 x y - 12 x y - 30 y ^ { 2 }10x2+25xy−12xy−30y2

Factor by Grouping $10 x ^ { 2 } + 25 x y - 12 x y - 30 y ^ { 2 }$