Solve the problem.
-$$\frac { 64 x ^ { 4 } - 48 x ^ { 3 } + 40 x ^ { 2 } } { 8 x ^ { 3 } }$$
A) $8 x - 48 x ^ { 3 } + \frac { 5 } { x }$
B) $8 x - 6$
C) $8 x - 6 + \frac { 5 } { x }$
D) $13 x - 6$

Name: Solve the problem. -\[\frac { 64 x ^ { 4 } - 48 x ^ { 3 } + 40 x ^ { 2 } } { 8 x ^ { 3 } }\] A) $8 x - 48 x ^ { 3 } + \frac { 5 } { x }$ B) $8 x - 6$ C) $8 x - 6 + \frac { 5 } { x }$ D) $13 x - 6$
Brand: Quizplus
Rating: 4.9 (29 reviews)

Question

Quizplus · Accepted Answer

Dividing each term in the numerator by $8x^3$ gives $8x - 6 + \frac{5}{x}$.

Solve the Problem 64x4−48x3+40x28x3\frac { 64 x ^ { 4 } - 48 x ^ { 3 } + 40 x ^ { 2 } } { 8 x ^ { 3 } }8x364x4−48x3+40x2​

Solve the Problem $\frac { 64 x ^ { 4 } - 48 x ^ { 3 } + 40 x ^ { 2 } } { 8 x ^ { 3 } }$