Identify the type of graph.
-$$- x ^ { 2 } - 10 x + 6 y ^ { 2 } + 12 y = 16$$
A) The graph is an ellipse with center $\left( - \frac { 6 } { 5 } , 2 \right)$.
B) The graph is a circle with center $\left( \frac { 6 } { 5 } , - 2 \right)$.
C) The equation has no graph.
D) The graph is a hyperbola opening to the right and left.

Question

Quizplus · Accepted Answer

The equation is a hyperbola because it has both $x^2$ and $y^2$ terms with opposite signs.

Identify the Type of Graph −x2−10x+6y2+12y=16- x ^ { 2 } - 10 x + 6 y ^ { 2 } + 12 y = 16−x2−10x+6y2+12y=16

Identify the Type of Graph $- x ^ { 2 } - 10 x + 6 y ^ { 2 } + 12 y = 16$