Match the equation of a hyperbola with its description.
-$$\frac { ( x + 2 ) ^ { 2 } } { 25 } - \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$$
A) center (3, 2); vertical transverse axis
B) center (-2, -3); horizontal transverse axis
C) center (2, 3); horizontal transverse axis
D) center (-3, -2); vertical transverse axis

Question

Quizplus · Accepted Answer

The equation of a hyperbola in the form $\frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1$ has a center at (h, k) and a horizontal transverse axis if $a^2$ is under the $x$ term. For the given equation, the center is at (-2, -3), and since the $x$ term is positive and comes first, it has a horizontal transverse axis, matching option B.

Match the Equation of a Hyperbola with Its Description (x+2)225−(y+3)216=1\frac { ( x + 2 ) ^ { 2 } } { 25 } - \frac { ( y + 3 ) ^ { 2 } } { 16 } = 125(x+2)2​−16(y+3)2​=1

Match the Equation of a Hyperbola with Its Description $\frac { ( x + 2 ) ^ { 2 } } { 25 } - \frac { ( y + 3 ) ^ { 2 } } { 16 } = 1$