Write an equation for the ellipse.
-center at origin; length of major axis $12 ; \mathrm { y }$-intercepts $( 0 , \pm 5 )$
A) $\frac { x ^ { 2 } } { 6 } + \frac { y ^ { 2 } } { 5 } = 1$
B) $\frac { x ^ { 2 } } { 25 } + \frac { y ^ { 2 } } { 36 } = 1$
C) $\frac { x ^ { 2 } } { 5 } + \frac { y ^ { 2 } } { 6 } = 1$
D) $\frac { x ^ { 2 } } { 36 } + \frac { y ^ { 2 } } { 25 } = 1$

Question

Quizplus · Accepted Answer

The length of the major axis is 12, which means the major radius (a) is 6, so $a^2 = 36$. The y-intercepts at $\pm 5$ indicate the minor radius (b) is 5, so $b^2 = 25$. Since the ellipse is centered at the origin and the major axis length suggests it's horizontal, the correct equation is $\frac{x^2}{36} + \frac{y^2}{25} = 1$.

Write an Equation for the Ellipse 12;y12 ; \mathrm { y }12;y

Write an Equation for the Ellipse $12 ; \mathrm { y }$