Write out the first five terms of the sequence.
-$$a _ { n } = ( - 1 ) ^ { n - 1 } ( 7 n - 8 )$$
A) $1,6 , - 13 , - 20 , - 27$
B) $- 1,6,13,20,27$
C) $- 1 , - 22,13 , - 20,43$
D) $- 1 , - 6,13 , - 20,27$

Question

Quizplus · Accepted Answer

To find the first five terms of the sequence, substitute $n = 1, 2, 3, 4, 5$ into the formula $a_n = (-1)^{n-1}(7n - 8)$. For $n=1$, $a_1 = (-1)^0(7(1) - 8) = 1(-1) = -1$. For $n=2$, $a_2 = (-1)^1(7(2) - 8) = -1(6) = -6$. For $n=3$, $a_3 = (-1)^2(7(3) - 8) = 1(13) = 13$. For $n=4$, $a_4 = (-1)^3(7(4) - 8) = -1(20) = -20$. For $n=5$, $a_5 = (-1)^4(7(5) - 8) = 1(27) = 27$. Therefore, the first five terms are $-1, -6, 13, -20, 27$.

Write Out the First Five Terms of the Sequence an=(−1)n−1(7n−8)a _ { n } = ( - 1 ) ^ { n - 1 } ( 7 n - 8 )an​=(−1)n−1(7n−8)

Write Out the First Five Terms of the Sequence $a _ { n } = ( - 1 ) ^ { n - 1 } ( 7 n - 8 )$