Consider the function h as defined. Find functions f and g so that (f  g)(x) = h(x).
-$$h ( x ) = \frac { 3 } { x ^ { 2 } } + 8$$
A) $f ( x ) = \frac { 3 } { x ^ { 2 } } , g ( x ) = 8$
B) $f ( x ) = x , g ( x ) = \frac { 3 } { x } + 8$
C) $f ( x ) = x + 8 , g ( x ) = \frac { 3 } { x ^ { 2 } }$
D) $f ( x ) = \frac { 1 } { x } , g ( x ) = \frac { 3 } { x } + 8$

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The Answer of Consider the function h as defined. Find functions f and g so that (f  g)(x) = h(x).
-$$h ( x ) = \frac { 3 } { x ^ { 2 } } + 8$$
A) $f ( x ) = \frac { 3 } { x ^ { 2 } } , g ( x ) = 8$
B) $f ( x ) = x , g ( x ) = \frac { 3 } { x } + 8$
C) $f ( x ) = x + 8 , g ( x ) = \frac { 3 } { x ^ { 2 } }$
D) $f ( x ) = \frac { 1 } { x } , g ( x ) = \frac { 3 } { x } + 8$

Consider the Function H as Defined h(x)=3x2+8h ( x ) = \frac { 3 } { x ^ { 2 } } + 8h(x)=x23​+8

Consider the Function H as Defined $h ( x ) = \frac { 3 } { x ^ { 2 } } + 8$