Find the center-radius form of the equation of the circle.
-center $( 0,6 )$, radius 10
A) $( x + 6 ) ^ { 2 } + y ^ { 2 } = 100$
B) $( x - 6 ) ^ { 2 } + y ^ { 2 } = 100$
C) $x ^ { 2 } + ( y - 6 ) ^ { 2 } = 100$
D) $x ^ { 2 } + ( y + 6 ) ^ { 2 } = 10$

Question

Quizplus · Accepted Answer

The center-radius form of a circle's equation is $(x - h)^2 + (y - k)^2 = r^2$, where $(h, k)$ is the center and $r$ is the radius. For a center at $(0, 6)$ and radius 10, the equation is $x^2 + (y - 6)^2 = 100$.

Find the Center-Radius Form of the Equation of the Circle (0,6)( 0,6 )(0,6)

Find the Center-Radius Form of the Equation of the Circle $( 0,6 )$