Round to the nearest tenth unless indicated otherwise.
-The force needed to keep a car from skidding on a curve varies jointly as the weight of the car and the square of the car's speed, and inversely as the radius of the curve. If a force of 3600 pounds is
Needed to keep an 1800 pound car traveling at 20 mph from skidding on a curve of radius 600 feet,
What force would be required to keep the same car from skidding on a curve of radius 590 feet at
60 mph? Round your answer to the nearest pound of force.
A) 32,949 lb
B) 32,817 lb
C) 32,981 lb
D) 33,519 lb

Question

Quizplus · Accepted Answer

The force needed to keep a car from skidding on a curve is given by $F = k \cdot \frac{Wv^2}{r}$, where $F$ is the force, $W$ is the weight of the car, $v$ is the speed of the car, $r$ is the radius of the curve, and $k$ is a constant of proportionality. Given $F = 3600$ pounds for a 1800 pound car at 20 mph and a radius of 600 feet, we can find $k$ and then use it to calculate the force required for the same car at 60 mph on a curve of radius 590 feet. The calculation shows that the force required is approximately 32,949 pounds, rounding to the nearest pound.

Round to the Nearest Tenth Unless Indicated Otherwise