Give the equations of any horizontal asymptotes.
-$$h ( x ) = \frac { 2 - 4 x } { - 6 x + 3 }$$
A) $y = \frac { 2 } { 3 }$
B) none
C) $y = 0$
D) $y = - \frac { 2 } { 3 }$

Name: Give the equations of any horizontal asymptotes. -\[h ( x ) = \frac { 2 - 4 x } { - 6 x + 3 }\] A) $y = \frac { 2 } { 3 }$ B) none C) $y = 0$ D) $y = - \frac { 2 } { 3 }$
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The horizontal asymptote is $y = \frac { 2 } { 3 }$ because as $x$ approaches infinity or negative infinity, the fraction approaches $\frac { 2 } { 3 }$.

Give the Equations of Any Horizontal Asymptotes h(x)=2−4x−6x+3h ( x ) = \frac { 2 - 4 x } { - 6 x + 3 }h(x)=−6x+32−4x​

Give the Equations of Any Horizontal Asymptotes $h ( x ) = \frac { 2 - 4 x } { - 6 x + 3 }$