Use Descartes' Rule of Signs to Determine the Possible Number $$f ( x ) = 3 x ^ { 6 } - 7 x ^ { 4 } - 7 x ^ { 3 } + 4 x ^ { 2 } - 5 x$$

Use Descartes' Rule of Signs to determine the possible number of positive real zeros and the possible number of negative
real zeros for the function.
- $$f ( x ) = 3 x ^ { 6 } - 7 x ^ { 4 } - 7 x ^ { 3 } + 4 x ^ { 2 } - 5 x$$

A)

$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 2 & 3 & 1 \\2 & 1 & 3 \\0 & 3 & 3 \\0 & 1 & 5\end{array}$

B)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 3 & 2 & 1 \\3 & 0 & 3 \\1 & 2 & 3 \\1 & 0 & 5\end{array}$

C)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 2 & 0 & 4 \\0 & 0 & 6\end{array}$

D)
$\begin{array}{c|c|c}\text { Positive } & \text { Negative } & \text { Nonreal Complex } \\\hline 3 & 2 & 1 \\1 & 2 & 3\end{array}$