Round your answer to the nearest tenth, when appropriate. Use the formula $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }$ needed.
-Find the $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$if the $\mathrm { pH } = 2.3$.
A) $2.7 \times 10 ^ { 1 }$
B) $5.0 \times 10 ^ { - 3 }$
C) $2.0 \times 10 ^ { 2 }$
D) $3.6 \times 10 ^ { - 1 }$

Question

Quizplus · Accepted Answer

The concentration of $\mathrm{H}_3\mathrm{O}^+$ can be found by rearranging the pH formula to $\left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-\mathrm{pH}}$. Substituting $\mathrm{pH} = 2.3$ gives $\left[ \mathrm{H}_3\mathrm{O}^+ \right] = 10^{-2.3} = 5.0 \times 10^{-3}$.

Round Your Answer to the Nearest Tenth, When Appropriate pH=−log⁡[H3O+],as \mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }pH=−log[H3​O+],as

Round Your Answer to the Nearest Tenth, When Appropriate $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }$