Round your answer to the nearest tenth, when appropriate. Use the formula $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }$ needed.
-Find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$if the $\mathrm { pH } = 11$.
A) $3.0 \times 10 ^ { - 11 }$
B) $2.0 \times 1011$
C) $1.0 \times 1011$
D) $1.0 \times 10 ^ { - 11 }$

Question

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The Answer of Round your answer to the nearest tenth, when appropriate. Use the formula $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }$ needed.
-Find $\left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right]$if the $\mathrm { pH } = 11$.
A) $3.0 \times 10 ^ { - 11 }$
B) $2.0 \times 1011$
C) $1.0 \times 1011$
D) $1.0 \times 10 ^ { - 11 }$

Round Your Answer to the Nearest Tenth, When Appropriate pH=−log⁡[H3O+],as \mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }pH=−log[H3​O+],as

Round Your Answer to the Nearest Tenth, When Appropriate $\mathrm { pH } = - \log \left[ \mathrm { H } _ { 3 } \mathrm { O } ^ { + } \right] , \text {as }$