Solve the right triangle. If two sides are given, give angles in degrees and minutes.
-$$A = 79 ^ { \circ } 32 ^ { \prime } , c = 264 \mathrm {~m} , C = 90 ^ { \circ }$$
Round side lengths to two decimal places, if necessary.
A) $B = 11 ^ { \circ } 18 ^ { \prime } , a = 259.81 \mathrm {~m} , \mathrm {~b} = 47.96 \mathrm {~m}$
B) $B = 10 ^ { \circ } 32 ^ { \prime } , a = 260.81 \mathrm {~m} , \mathrm {~b} = 40.96 \mathrm {~m}$
C) $\mathrm { B } = 10 ^ { \circ } 28 ^ { \prime } , \mathrm { a } = 259.81 \mathrm {~m} , \mathrm {~b} = 54.96 \mathrm {~m}$
D) $B = 10 ^ { \circ } 28 ^ { \prime } , a = 259.61 \mathrm {~m} , \mathrm {~b} = 47.96 \mathrm {~m}$

Question

Quizplus · Accepted Answer

Angle B is calculated as $90^\circ - 79^\circ 32'$, which equals $10^\circ 28'$. Using the sine rule, $a = c \cdot \sin(A)$ and $b = c \cdot \sin(B)$, we find $a = 259.61 \, \text{m}$ and $b = 47.96 \, \text{m}$.

Solve the Right Triangle A=79∘32′,c=264 m,C=90∘A = 79 ^ { \circ } 32 ^ { \prime } , c = 264 \mathrm {~m} , C = 90 ^ { \circ }A=79∘32′,c=264 m,C=90∘

Solve the Right Triangle $A = 79 ^ { \circ } 32 ^ { \prime } , c = 264 \mathrm {~m} , C = 90 ^ { \circ }$