Find the phase shift of the function.
-$$y = - 4 + 3 \sin \left( 4 x - \frac { \pi } { 2 } \right)$$
A) $\frac { \pi } { 8 }$ units to the right
B) $\frac { \pi } { 6 }$ units to the right
C) $\frac { \pi } { 2 }$ units to the left
D) $\frac { \pi } { 8 }$ units to the left

Question

Quizplus · Accepted Answer

The phase shift of a sine function in the form $y = a \sin(bx - c) + d$ is calculated as $\frac{c}{b}$. Here, $c = \frac{\pi}{2}$ and $b = 4$, so the phase shift is $\frac{\pi/2}{4} = \frac{\pi}{8}$ units to the right.

Find the Phase Shift of the Function y=−4+3sin⁡(4x−π2)y = - 4 + 3 \sin \left( 4 x - \frac { \pi } { 2 } \right)y=−4+3sin(4x−2π​)

Find the Phase Shift of the Function $y = - 4 + 3 \sin \left( 4 x - \frac { \pi } { 2 } \right)$