Solve the problem
-A wheel is rotating at 7 radians/sec, and the wheel has a 48 -inch diameter. To the nearest foot, what is the speed of a point on the rim in $\mathrm { ft } / \mathrm { min }$ ?
A) $840 \mathrm { ft } / \mathrm { min }$
B) $845 \mathrm { ft } / \mathrm { min }$
C) $830 \mathrm { ft } / \mathrm { min }$
D) $835 \mathrm { ft } / \mathrm { min }$

Question

Quizplus · Accepted Answer

The speed of a point on the rim is given by the formula $v = r\omega$, where $v$ is the linear speed, $r$ is the radius of the wheel, and $\omega$ is the angular speed. Here, $r = 48/2 = 24$ inches $= 2$ feet (since there are 12 inches in a foot), and $\omega = 7$ radians/sec. Thus, $v = 2 \times 7 = 14$ ft/sec. To convert this to ft/min, multiply by 60 (since there are 60 seconds in a minute), giving $14 \times 60 = 840$ ft/min.

Solve the Problem -A Wheel Is Rotating at 7 Radians/sec ft/min\mathrm { ft } / \mathrm { min }ft/min

Solve the Problem
-A Wheel Is Rotating at 7 Radians/sec $\mathrm { ft } / \mathrm { min }$