Find the exact value of s in the given interval that has the given circular function value.
-$\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }$
A) $s = \frac { \pi } { 4 }$

B) $s = \frac { 5 \pi } { 6 }$

C) $s = \frac { 2 \pi } { 3 }$

D) $\mathrm { s } = \frac { 3 \pi } { 4 }$

Question

Find the exact value of s in the given interval that has the given circular function value.
-$\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }$
A) $s = \frac { \pi } { 4 }$

B) $s = \frac { 5 \pi } { 6 }$

C) $s = \frac { 2 \pi } { 3 }$

D) $\mathrm { s } = \frac { 3 \pi } { 4 }$

Quizplus · Accepted Answer

The Answer of Find the exact value of s in the given interval that has the given circular function value.
-$\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }$
A) $s = \frac { \pi } { 4 }$

B) $s = \frac { 5 \pi } { 6 }$

C) $s = \frac { 2 \pi } { 3 }$

D) $\mathrm { s } = \frac { 3 \pi } { 4 }$

Find the Exact Value of S in the Given Interval [π2,π];sin⁡s=22\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }[2π​,π];sins=22​​

Find the Exact Value of S in the Given Interval $\left[ \frac { \pi } { 2 } , \pi \right] ; \sin \mathrm { s } = \frac { \sqrt { 2 } } { 2 }$