Vector v has the given magnitude and direction. Find the horizontal or vertical component of v, as indicated, if $\theta$ is the
direction angle of v from the horizontal. Round to the nearest tenth when necessary.
-$\alpha = 33.9 ^ { \circ } , | \mathbf { v } | = 82.9 ;$ Find the horizontal component of $\mathbf { v }$
A) $46.2$
B) $22.6$
C) 115
D) $68.8$

Question

Quizplus · Accepted Answer

The horizontal component of a vector can be found using the formula $v_{x} = |v| \cos(\theta)$, where $|v|$ is the magnitude of the vector and $\theta$ is the direction angle from the horizontal. For this question, $|v| = 82.9$ and $\theta = 33.9^\circ$. Thus, the horizontal component is $82.9 \cos(33.9^\circ) \approx 68.8$.

Vector V Has the Given Magnitude and Direction θ\thetaθ Is the Direction Angle of V from the Horizontal

Vector V Has the Given Magnitude and Direction $\theta$ Is the
Direction Angle of V from the Horizontal