Find the area of triangle ABC with the given parts. Round to the nearest tenth when necessary.
-Two ships leave a harbor together traveling on courses that have an angle of $128 ^ { \circ }$ between them. If they each travel 543 miles, how far apart are they (to the nearest mile)?
A) $976 \mathrm { mi }$
B) $42 \mathrm { mi }$
C) $476 \mathrm { mi }$
D) $1952 \mathrm { mi }$

Question

Quizplus · Accepted Answer

Using the Law of Cosines, $c^2 = a^2 + b^2 - 2ab\cos(C)$, where $a = 543$, $b = 543$, and $C = 128^\circ$, we find the distance between the ships to be approximately 976 miles.

Find the Area of Triangle ABC with the Given Parts 128∘128 ^ { \circ }128∘

Find the Area of Triangle ABC with the Given Parts $128 ^ { \circ }$