Find the matrix product when possible.
-$$\left[ \begin{array} { r r }
0 & - 3 \
4 & 3
\end{array} \right] \left[ \begin{array} { l l }
- 2 & 0 \
- 1 & 1
\end{array} \right]$$
A)
$$\left[ \begin{array} { r r }
3 & - 3 \
- 11 & 3
\end{array} \right]$$

B)
$$\left[ \begin{array} { r r }
- 3 & 3 \
- 5 & - 11
\end{array} \right]$$

C)
$$\left[ \begin{array} { r r }
- 8 & - 6 \
4 & 6
\end{array} \right]$$

D)
$$\left[ \begin{array} { r r }
0 & 6 \
- 4 & 3
\end{array} \right]$$

Question

Find the matrix product when possible.
-$$\left[ \begin{array} { r r } 
0 & - 3 \
4 & 3
\end{array} \right] \left[ \begin{array} { l l } 
- 2 & 0 \
- 1 & 1
\end{array} \right]$$
A)
$$\left[ \begin{array} { r r } 
3 & - 3 \
- 11 & 3
\end{array} \right]$$

B)
$$\left[ \begin{array} { r r } 
- 3 & 3 \
- 5 & - 11
\end{array} \right]$$

C)
$$\left[ \begin{array} { r r } 
- 8 & - 6 \
4 & 6
\end{array} \right]$$

D)
$$\left[ \begin{array} { r r } 
0 & 6 \
- 4 & 3
\end{array} \right]$$

Quizplus · Accepted Answer

To find the product of two matrices, multiply each element of the rows of the first matrix by the corresponding element of the columns of the second matrix and add them together. For the given matrices, the calculations are as follows:1. For the element in the first row, first column: $0*(-2) + (-3)*(-1) = 0 + 3 = 3$2. For the element in the first row, second column: $0*0 + (-3)*1 = 0 - 3 = -3$3. For the element in the second row, first column: $4*(-2) + 3*(-1) = -8 - 3 = -11$4. For the element in the second row, second column: $4*0 + 3*1 = 0 + 3 = 3$Thus, the product of the matrices is $\left[ \begin{array} { r r } 3 & - 3 \ - 11 & 3 \end{array} \right]$.

Find the Matrix Product When Possible [0−343][−20−11]\left[ \begin{array} { r r } 0 & - 3 \\4 & 3\end{array} \right] \left[ \begin{array} { l l } - 2 & 0 \\- 1 & 1\end{array} \right][04​−33​][−2−1​01​]

Find the Matrix Product When Possible $\left[ \begin{array} { r r } 0 & - 3 \\4 & 3\end{array} \right] \left[ \begin{array} { l l } - 2 & 0 \\- 1 & 1\end{array} \right]$