The function F described by F(C)=$\frac { 9 } { 5 }$C+32 gives the Fahrenheit temperature corresponding to the Celsius
temperature C . Find and interpret F(-20) .
A) $- 112 ^ { \circ } \mathrm { F } : \mathrm { A }$temperature of $- 20 ^ { \circ } \mathrm { C }$ is equivalent to $- 112 ^ { \circ } \mathrm { F }$
B) $- 4 ^ { \circ } \mathrm { F } ; \mathrm { A }$temperature of $- 20 ^ { \circ } \mathrm { C }$ is equivalent to $- 4 ^ { \circ } \mathrm { F }$
C) $- 4 ^ { \circ } \mathrm { F } : \mathrm { A }$temperature of $- 4 ^ { \circ } \mathrm { C }$ is equivalent to $- 20 ^ { \circ } \mathrm { F }$
D) $- 40 ^ { \circ } \mathrm { F } ; \mathrm { A }$temperature of $$- 20 ^ { \circ } \mathrm { C }$$ is equivalent to $$- 40 ^ { \circ } \mathrm { F }$$

Question

The function F described by F(C)=$\frac { 9 } { 5 }$C+32  gives the Fahrenheit temperature corresponding to the Celsius
temperature  C . Find and interpret  F(-20) .
A) $- 112 ^ { \circ } \mathrm { F } : \mathrm { A }$temperature of $- 20 ^ { \circ } \mathrm { C }$ is equivalent to $- 112 ^ { \circ } \mathrm { F }$
B) $- 4 ^ { \circ } \mathrm { F } ; \mathrm { A }$temperature of $- 20 ^ { \circ } \mathrm { C }$ is equivalent to $- 4 ^ { \circ } \mathrm { F }$
C) $- 4 ^ { \circ } \mathrm { F } : \mathrm { A }$temperature of $- 4 ^ { \circ } \mathrm { C }$ is equivalent to $- 20 ^ { \circ } \mathrm { F }$
D) $- 40 ^ { \circ } \mathrm { F } ; \mathrm { A }$temperature of $$- 20 ^ { \circ } \mathrm { C }$$ is equivalent to $$- 40 ^ { \circ } \mathrm { F }$$

Quizplus · Accepted Answer

Plugging -20 for C in the formula F(C) = (9/5)C + 32 gives F(-20) = (9/5)(-20) + 32 = -36 + 32 = -4, so a temperature of -20°C is equivalent to -4°F.

The Function F Described by F(C)= 95\frac { 9 } { 5 }59​

The Function F Described by F(C)= $\frac { 9 } { 5 }$