The distance an object is from the ground after being tossed from a hot air balloon 770 feet in the air is a function of time and given by $$h ( t ) = - 16.1 t ^ { 2 } + 5.7 t + 770$$ where h is height in feet and t is the number of seconds
The object has been in the air. Find h(5.5) and explain its meaning.
A) 314.33 feet; After the object has been in the air 5.5 seconds, it is 314.33 feet above the ground.
B) 712.80 feet; After the object has been in the air 712.80 seconds, it is 5.5 feet above the ground.
C) 251.63 feet; After the object has been in the air 5.5 seconds, it is 251.63 feet above the ground.
D) 712.80 feet; After the object has been in the air 5.5 seconds, it is 314.33 feet above the ground.

Question

Quizplus · Accepted Answer

To find $h(5.5)$, substitute $t = 5.5$ into the given function: $h(5.5) = -16.1(5.5)^2 + 5.7(5.5) + 770$. Calculating this gives $h(5.5) = 314.33$ feet. This means that after 5.5 seconds, the object is 314.33 feet above the ground.

The Distance an Object Is from the Ground After Being h(t)=−16.1t2+5.7t+770h ( t ) = - 16.1 t ^ { 2 } + 5.7 t + 770h(t)=−16.1t2+5.7t+770

The Distance an Object Is from the Ground After Being $h ( t ) = - 16.1 t ^ { 2 } + 5.7 t + 770$