Solve the formula for the specified variable.
-$\mathrm { A } = \frac { 1 } { 2 } \mathrm {~h} \left( \mathrm {~b} _ { 1 } + \mathrm { b } _ { 2 } \right)$ for $\mathrm { b } _ { 1 }$
A) $b _ { 1 } = \frac { h b _ { 2 } - 2 A } { h }$
B) $b _ { 1 } = \frac { 2 \mathrm { Ab } _ { 2 } - \mathrm { h } } { \mathrm { h } }$
C) $b _ { 1 } = \frac { A - h b _ { 2 } } { 2 h }$
D) $b _ { 1 } = \frac { 2 A - h b _ { 2 } } { h }$

Question

Quizplus · Accepted Answer

To solve for $b_1$, first multiply both sides by 2 to get rid of the fraction: $2A = h(b_1 + b_2)$. Then, isolate $b_1$ by subtracting $hb_2$ from both sides: $2A - hb_2 = hb_1$. Finally, divide both sides by $h$ to solve for $b_1$, resulting in $b_1 = \frac{2A - hb_2}{h}$.

Solve the Formula for the Specified Variable A=12 h( b1+b2)\mathrm { A } = \frac { 1 } { 2 } \mathrm {~h} \left( \mathrm {~b} _ { 1 } + \mathrm { b } _ { 2 } \right)A=21​ h( b1​+b2​)

Solve the Formula for the Specified Variable $\mathrm { A } = \frac { 1 } { 2 } \mathrm {~h} \left( \mathrm {~b} _ { 1 } + \mathrm { b } _ { 2 } \right)$