Suppose that y varies directly as the $$3 / 2 \text { power of } x \text {, and that } y = 192 \text { when } x = 16 . \text { Find } y \text { when } x = 9$$ .
A) 81
B) 48
C) 3
D) 192

Question

Quizplus · Accepted Answer

y varies directly as the $$3 / 2 \text { power of } x \text {, so } y = kx^{3 / 2} \text { for some constant } k$$. We can find k by using the given information: $$y = 192 \text { when } x = 16$$. Substituting these values into the equation, we get $$192 = k(16)^{3 / 2} = k(64) = 64k$$. Therefore, $$k = 3$$. Now we can find y when x = 9: $$y = 3(9)^{3 / 2} = 3(27) = 81$$.

Suppose That Y Varies Directly as The 3/2 power of x, and that y=192 when x=16. Find y when x=93 / 2 \text { power of } x \text {, and that } y = 192 \text { when } x = 16 . \text { Find } y \text { when } x = 93/2 power of x, and that y=192 when x=16. Find y when x=9

Suppose That Y Varies Directly as The $3 / 2 \text { power of } x \text {, and that } y = 192 \text { when } x = 16 . \text { Find } y \text { when } x = 9$