Use factoring to solve the equation
-$$20 y ^ { 2 } + 41 y + 20 = 0$$
A) $- \frac { 1 } { 5 } , - \frac { 1 } { 4 }$
B) $- \frac { 4 } { 5 } , - \frac { 5 } { 4 }$
C) $\frac { 4 } { 5 } , \frac { 5 } { 4 }$
D) $\frac { 4 } { 5 } , - \frac { 5 } { 4 }$

Question

Quizplus · Accepted Answer

The quadratic can be factored as $(5y + 4)(4y + 5) = 0$, giving solutions $y = -\frac{4}{5}$ and $y = -\frac{5}{4}$.

Use Factoring to Solve the Equation - 20y2+41y+20=020 y ^ { 2 } + 41 y + 20 = 020y2+41y+20=0

Use Factoring to Solve the Equation
- $20 y ^ { 2 } + 41 y + 20 = 0$