Solve the equation
-$\sqrt { 2 x ^ { 2 } + 42 } = \sqrt { x ^ { 2 } + 13 x }$
A) x=21, x=-7
B) x=6, x=7
C) x=21, x= $\frac { 13 } { 2 }$
D) x=$\frac { 13 } { 2 }$, x=-6

Question

Solve the equation
-$\sqrt { 2 x ^ { 2 } + 42 } = \sqrt { x ^ { 2 } + 13 x }$
A)  x=21, x=-7 
B)  x=6, x=7 
C)  x=21, x= $\frac { 13 } { 2 }$
D)  x=$\frac { 13 } { 2 }$, x=-6

Quizplus · Accepted Answer

The Answer of Solve the equation
-$\sqrt { 2 x ^ { 2 } + 42 } = \sqrt { x ^ { 2 } + 13 x }$
A)  x=21, x=-7 
B)  x=6, x=7 
C)  x=21, x= $\frac { 13 } { 2 }$
D)  x=$\frac { 13 } { 2 }$, x=-6

Solve the Equation - 2x2+42=x2+13x\sqrt { 2 x ^ { 2 } + 42 } = \sqrt { x ^ { 2 } + 13 x }2x2+42​=x2+13x​

Solve the Equation
- $\sqrt { 2 x ^ { 2 } + 42 } = \sqrt { x ^ { 2 } + 13 x }$