A certain noise measures 79 decibels. If the intensity is multiplied by 10, how many decibels will the new noise measure? $$\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)$$
A) 79 decibels
B) 89 decibels
C) 80 decibels
D) 790 decibels

Question

Quizplus · Accepted Answer

The decibel level increases by 10 decibels for every tenfold increase in intensity, so multiplying the intensity by 10 increases the noise level from 79 to 89 decibels.

A Certain Noise Measures 79 Decibels L=10log⁡(II0)\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)L=10log(I0​I​)

A Certain Noise Measures 79 Decibels $\mathrm { L } = 10 \log \left( \frac { \mathrm { I } } { \mathrm { I } _ { 0 } } \right)$