Give the equations of any vertical asymptotes for the graphs of the rational functions.
-$$h ( x ) = \frac { ( x - 6 ) ( x + 1 ) } { x ^ { 2 } - 4 }$$
A) $x = - 6 , x = 1$
B) $x = 2 , x = - 2$
C) $x = 6 , x = - 1$
D) none

Question

Quizplus · Accepted Answer

Vertical asymptotes occur where the denominator of a rational function is zero (and the numerator is not zero at those points). For $h(x) = \frac{(x - 6)(x + 1)}{x^2 - 4}$, the denominator is $x^2 - 4 = (x - 2)(x + 2)$. Setting this equal to zero gives $x = 2$ and $x = -2$, which are the locations of the vertical asymptotes.

Give the Equations of Any Vertical Asymptotes for the Graphs h(x)=(x−6)(x+1)x2−4h ( x ) = \frac { ( x - 6 ) ( x + 1 ) } { x ^ { 2 } - 4 }h(x)=x2−4(x−6)(x+1)​

Give the Equations of Any Vertical Asymptotes for the Graphs $h ( x ) = \frac { ( x - 6 ) ( x + 1 ) } { x ^ { 2 } - 4 }$