One solution of a polynomial equation is given. Use synthetic division to find any remaining solutions.
-$$6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$$
A) $\frac { 1 } { 3 } , 2$
B) $\frac { 1 } { 3 } , \frac { 1 } { 3 }$
C) $- 2 , \frac { 1 } { 3 }$
D) $\pm \frac { 1 } { 3 }$

Question

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The Answer of One solution of a polynomial equation is given. Use synthetic division to find any remaining solutions.
-$$6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$$
A) $\frac { 1 } { 3 } , 2$
B) $\frac { 1 } { 3 } , \frac { 1 } { 3 }$
C) $- 2 , \frac { 1 } { 3 }$
D) $\pm \frac { 1 } { 3 }$

One Solution of a Polynomial Equation Is Given 6x3+16x2+6x−4=0;−16 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 16x3+16x2+6x−4=0;−1

One Solution of a Polynomial Equation Is Given $6 x ^ { 3 } + 16 x ^ { 2 } + 6 x - 4 = 0 ; - 1$