Use factoring by grouping to solve the equation.
-$$x ^ { 3 } + 2 x ^ { 2 } - 16 x - 32 = 0$$
A) $- 4 , - 2,2$
B) $2 , - 4,4$
C) $- 2,2,4$
D) $- 2 , - 4,4$

Question

Quizplus · Accepted Answer

The equation can be factored by grouping: $(x^3 + 2x^2) + (-16x - 32) = x^2(x + 2) - 16(x + 2) = (x^2 - 16)(x + 2)$. Further factoring gives $(x - 4)(x + 4)(x + 2) = 0$, leading to roots $x = 4, x = -4, x = -2$.

Use Factoring by Grouping to Solve the Equation x3+2x2−16x−32=0x ^ { 3 } + 2 x ^ { 2 } - 16 x - 32 = 0x3+2x2−16x−32=0

Use Factoring by Grouping to Solve the Equation $x ^ { 3 } + 2 x ^ { 2 } - 16 x - 32 = 0$