Solve the polynomial equation.
-$$( 3 x + 1 ) ( x - 2 ) ^ { 2 } ( x + 6 ) = 0$$
A) $\frac { 1 } { 3 } , - 2,6$
B) $- \frac { 1 } { 3 } , 2 , - 6$
C) $- \frac { 1 } { 3 } , - 2,2 , - 6$
D) $- 1,4 , - 6$

Question

Quizplus · Accepted Answer

The equation is solved by setting each factor equal to zero: $3x + 1 = 0$, $x - 2 = 0$, and $x + 6 = 0$. Solving these gives $x = -\frac{1}{3}$, $x = 2$, and $x = -6$, respectively.

Solve the Polynomial Equation (3x+1)(x−2)2(x+6)=0( 3 x + 1 ) ( x - 2 ) ^ { 2 } ( x + 6 ) = 0(3x+1)(x−2)2(x+6)=0

Solve the Polynomial Equation $( 3 x + 1 ) ( x - 2 ) ^ { 2 } ( x + 6 ) = 0$