A trust account manager has $500,000 to be invested in three different accounts. The accounts pay 5%, 6%, and 8%, and the goal is to earn $34,000. Assuming that x dollars are invested at 5%, y dollars are invested at 6%, and Z dollars are invested at 8%, find y in terms of z.
A) $y = - 600,000 + 2 z$
B) $\mathrm { y } = 900,000 - 3 \mathrm { z }$
C) $y = - 400,000 + 2 z$
D) $\mathrm { y } = 1,100,000 - 3 \mathrm { z }$

Question

A trust account manager has $500,000 to be invested in three different accounts. The accounts pay 5%, 6%, and 8%, and the goal is to earn $34,000. Assuming that x dollars are invested at 5%, y dollars are invested at 6%, and Z dollars are invested at 8%, find y in terms of z. 
A) $y = - 600,000 + 2 z$
B) $\mathrm { y } = 900,000 - 3 \mathrm { z }$
C) $y = - 400,000 + 2 z$
D) $\mathrm { y } = 1,100,000 - 3 \mathrm { z }$

Quizplus · Accepted Answer

The total investment is $500,000, so $x + y + z = 500,000$. The interest goal is $34,000, so $0.05x + 0.06y + 0.08z = 34,000$. Solving these equations simultaneously, we find $y = 900,000 - 3z$.

A Trust Account Manager Has $500,000 to Be Invested in Three