The following system does not have a unique solution. Solve the system.
-$$\left\{ \begin{array} { r }
x - y + 3 z = - 8 \
x + 5 y + z = 40 \
5 x + y + 13 z = 10
\end{array} \right.$$
A) $x = 4 + z , y = - 18 - 2 z , z = z$
B) $x = 0 , y = - 1 , z = - 3$
C) inconsistent system, no solution
D) $x = 0 , y = 1 , z = - 3$

Question

The following system does not have a unique solution. Solve the system.
-$$\left\{ \begin{array} { r } 
x - y + 3 z = - 8 \
x + 5 y + z = 40 \
5 x + y + 13 z = 10
\end{array} \right.$$
A) $x = 4 + z , y = - 18 - 2 z , z = z$
B) $x = 0 , y = - 1 , z = - 3$
C) inconsistent system, no solution
D) $x = 0 , y = 1 , z = - 3$

Quizplus · Accepted Answer

The Answer of The following system does not have a unique solution. Solve the system.
-$$\left\{ \begin{array} { r } 
x - y + 3 z = - 8 \
x + 5 y + z = 40 \
5 x + y + 13 z = 10
\end{array} \right.$$
A) $x = 4 + z , y = - 18 - 2 z , z = z$
B) $x = 0 , y = - 1 , z = - 3$
C) inconsistent system, no solution
D) $x = 0 , y = 1 , z = - 3$

The Following System Does Not Have a Unique Solution {x−y+3z=−8x+5y+z=405x+y+13z=10\left\{ \begin{array} { r } x - y + 3 z = - 8 \\x + 5 y + z = 40 \\5 x + y + 13 z = 10\end{array} \right.⎩⎨⎧​x−y+3z=−8x+5y+z=405x+y+13z=10​

The Following System Does Not Have a Unique Solution $\left\{ \begin{array} { r } x - y + 3 z = - 8 \\x + 5 y + z = 40 \\5 x + y + 13 z = 10\end{array} \right.$